(w-2)(w+5)=(w^2)-4

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Solution for (w-2)(w+5)=(w^2)-4 equation: 



(w-2)(w+5)=(w^2)-4

We move all terms to the left:

(w-2)(w+5)-((w^2)-4)=0

We get rid of parentheses

-w^2+(w-2)(w+5)+4=0

We multiply parentheses ..

-w^2+(+w^2+5w-2w-10)+4=0

We add all the numbers together, and all the variables

-1w^2+(+w^2+5w-2w-10)+4=0

We get rid of parentheses

-1w^2+w^2+5w-2w-10+4=0

We add all the numbers together, and all the variables

3w-6=0

We move all terms containing w to the left, all other terms to the right

3w=6

w=6/3

w=2

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